If a 25 kVA transformer with 120/240-volt secondary windings is connected to a 240-volt load, what is the maximum amps it can deliver?

If a 25 kVA transformer with 120/240-volt secondary windings is connected to a 240-volt load, what is the maximum amps it can deliver?

• A. 104
• B. 100
• C. 120
• D. 90

Answer: (A)

To determine the maximum current that a 25 kVA transformer can deliver to a 240-volt load, we begin by using the formula for converting kVA to amps. The formula is: \[ I = \frac{P}{V} \] Where: - \( I \) is the current in amps, - \( P \) is the power in kVA (25 kVA in this case), and - \( V \) is the voltage in volts (240 V for the load). First, convert 25 kVA to watts, as 1 kVA is equivalent to 1000 watts: \[ P = 25 \, \text{kVA} \times 1000 \, \text{W/kVA} = 25000 \, \text{W} \] Now plug in the values into the formula: \[ I = \frac{25000 \, \text{W}}{240 \, \text{V}} \] Calculating this gives: \[ I = 104.17 \, \text{A} \] Since the question asks for the maximum amps the transformer can deliver, we round this value down to the nearest whole

To determine the maximum current that a 25 kVA transformer can deliver to a 240-volt load, we begin by using the formula for converting kVA to amps. The formula is:

[

I = \frac{P}{V}

]

Where:

• ( I ) is the current in amps,

• ( P ) is the power in kVA (25 kVA in this case), and

• ( V ) is the voltage in volts (240 V for the load).

First, convert 25 kVA to watts, as 1 kVA is equivalent to 1000 watts:

[

P = 25 , \text{kVA} \times 1000 , \text{W/kVA} = 25000 , \text{W}

]

Now plug in the values into the formula:

[

I = \frac{25000 , \text{W}}{240 , \text{V}}

]

Calculating this gives:

[

I = 104.17 , \text{A}

]

Since the question asks for the maximum amps the transformer can deliver, we round this value down to the nearest whole